<h2> Popuni praznijna mjesta</h2> <p>(a) 28 - 32x = 4(§§V0(1,8,1)§§ - 8x)</p> <p>(b) §§V1(-10,10,1)§§ + 28 = (6x + §§V2(-5,5,1)§§) · 7</p> <p>(c) §§V3(-10,10,1)§§ - §§V4(-10,10,1)§§ = -5(3x + 12)</p> <p>(d) 4a - §§V5(-10,10,1)§§ = 4a(§§V6(-5,5,1)§§ - 4ab)</p> <p>(e) 6y + §§V7(-10,10,1)§§ = -3y(§§V8(-5,5,1)§§ - 5x)</p> <p>(f) 18x + §§V9(-10,10,1)§§ = §§V10(-5,5,1)§§(3 + 5y)</p> <p>(g) §§V11(-10,10,1)§§ + 8ab = (6b - 2a) · §§V12(-5,5,1)§§</p>