Thiery

Squaring
<!doctype html> <html lang="hr"> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> <title>Gradski Portal</title> <link href="https://cdn.jsdelivr.net/npm/bootstrap@5.3.2/dist/css/bootstrap.min.css" rel="stylesheet" integrity="sha384-T3c6CoIi6uLrA9TneNEoa7RxnatzjcDSCmG1MXxSR1GAsXEV/Dwwykc2MPK8M2HN" crossorigin="anonymous"> <style> /* Dodatni CSS za stilizaciju */ .hero-section { background-image: url('gradska_pozadina.jpg'); /* Zamijeni s putanjom do tvoje slike */ background-size: cover; background-position: center; color: white; /* Tekst na hero sekciji */ padding: 100px 0; /* Vertikalni padding */ } </style> </head> <body> <nav class="navbar navbar-expand-lg navbar-light bg-light"> <div class="container"> <a class="navbar-brand" href="#">Gradski Portal</a> <button class="navbar-toggler" type="button" data-bs-toggle="collapse" data-bs-target="#navbarNav" aria-controls="navbarNav" aria-expanded="false" aria-label="Toggle navigation"> <span class="navbar-toggler-icon"></span> </button> <div class="collapse navbar-collapse" id="navbarNav"> <ul class="navbar-nav ms-auto"> <li class="nav-item"> <a class="nav-link active" aria-current="page" href="#">Naslovna</a> </li> <li class="nav-item"> <a class="nav-link" href="#">Vijesti</a> </li> <li class="nav-item"> <a class="nav-link" href="#">Događanja</a> </li> <li class="nav-item"> <a class="nav-link" href="#">Kontakt</a> </li> </ul> </div> </div> </nav> <section class="hero-section"> <div class="container"> <div class="row"> <div class="col-md-12 text-center"> <h1>Dobrodošli u [Ime Grada]</h1> <p class="lead">Sve informacije na jednom mjestu.</p> <a href="#" class="btn btn-primary btn-lg">Saznaj više</a> </div> </div> </div> </section> <section class="py-5 bg-light"> <div class="container"> <div class="row"> <div class="col-md-4"> <h2>Najnovije vijesti</h2> <p>Kratki opis najnovije vijesti.</p> <a href="#" class="btn btn-secondary">Pročitaj više</a> </div> <div class="col-md-4"> <h2>Događanja</h2> <p>Kratki opis nadolazećih događanja.</p> <a href="#" class="btn btn-secondary">Pogledaj više</a> </div> <div class="col-md-4"> <h2>Važne informacije</h2> <p>Korisne informacije za građane.</p> <a href="#" class="btn btn-secondary">Saznaj više</a> </div> </div> </div> </section> <footer class="bg-dark text-light py-3 text-center"> <div class="container"> <p>&copy; 2023 Gradski Portal</p> </div> </footer> <script src="https://cdn.jsdelivr.net/npm/bootstrap@5.3.2/dist/js/bootstrap.bundle.min.js" integrity="sha384-C6RzsynM9kWDrMNeT87bh95OGNyZPhcTNXj1NW7RuBCsyN/o0jlpcV8Qyq46cDfL" crossorigin="anonymous"></script> </body> </html> \begin{flalign*} & \textbf{Questions Mathématiques Complexes avec Variables} && \\ &(a) \quad \text{Calculez:} \\ & \quad \frac{ §§V1(3,10,1)§§ x^3 - §§V2(2,8,1)§§ x^2 + §§V3(1,5,1)§§ x }{x^2 - §§V4(1,4,1)§§ x + §§V5(2,6,1)§§ } \div \frac{ §§V6(2,8,1)§§ x^2 - §§V7(1,5,1)§§ x }{x^2 - §§V8(1,4,1)§§ x} && \\ &(b) \quad \text{Résolvez l'équation pour } x: \\ & \quad \sqrt{ §§V9(4,25,2)§§ x - §§V1(1,10,1)§§ } + §§V2(2,8,1)§§ = §§V3(5,15,1)§§ - \frac{ §§V4(2,10,1)§§ }{3}x && \\ &(c) \quad \text{Trouvez la valeur de } x \text{ qui satisfait l'équation suivante:} \\ & \quad \frac{ §§V5(3,12,1)§§ }{ §§V6(2,8,1)§§ }x - \frac{ §§V7(5,15,1)§§ }{ §§V8(3,12,1)§§ } = \frac{ x - §§V9(2,8,1)§§ }{ §§V1(4,16,1)§§ } + \frac{ §§V2(1,4,1)§§ }{ §§V3(8,32,1)§§ } && \\ &(d) \quad \text{Calculez la dérivée de la fonction suivante:} \\ & \quad f(x) = \frac{ e^{ §§V4(1,5,1)§§ x}}{x^2} + \ln( §§V5(2,8,1)§§ x) - \sqrt{ §§V6(1,9,2)§§ x + 1} && \\ &(e) \quad \text{Calculez l'intégrale définie suivante:} \\ & \quad \int_{ §§V7(1,4,1)§§ }^{ §§V8(6,12,1)§§ } (x^3 + 2x^2) \,dx + \int_{ §§V9(0,3,1)§§ }^{ §§V1(1,5,1)§§ } (2x + 1) \,dx && \\ &(f) \quad \text{Résolvez le système d'équations suivant:} \\ & \quad \begin{cases} 3x + 2y - z = §§V2(5,15,1)§§ \\ x - 3y + 4z = - §§V3(2,8,1)§§ \\ 2x + y - 2z = §§V4(7,21,1)§§ \end{cases} \\ &(g) \quad \text{Trouvez la solution de l'équation différentielle suivante:} \\ & \quad \frac{ dy }{dx} + 2y = 4x + 3e^{ §§V5(1,4,1)§§ x} && \\ &(h) \quad \text{Déterminez la valeur de } x \text{ qui satisfait l'équation suivante:} \\ & \quad \tan( §§V6(1,5,1)§§ x) + \frac{1}{ §§V7(2,8,1)§§ }\sin( §§V8(1,4,1)§§ x) = 1 && \\ &(i) \quad \text{Calculez l'intégrale indéfinie de la fonction suivante:} \\ & \quad \int ( §§V9(4,16,1)§§ x^3 + 2\sqrt{x} + \frac{1}{x^2}) \,dx && \\ \end{flalign*}
An error has occurred. This application may no longer respond until reloaded. Reload 🗙